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class Solution {
private TreeNode startNode;

public int findClosestLeaf(TreeNode root, int k) {
Map<TreeNode, TreeNode> nodeParent = new HashMap<>();
startNode = root;
buildParentMap(nodeParent, root.left, root, k);
buildParentMap(nodeParent, root.right, root, k);
Set<TreeNode> visited = new HashSet<>();
Deque<TreeNode> q = new ArrayDeque<>();
q.offer(startNode);
while (!q.isEmpty()) {
TreeNode currNode = q.poll();
if (currNode.left == null && currNode.right == null) {
return currNode.val;
}
visited.add(currNode);
if (currNode.left != null && !visited.contains(currNode.left)) {
q.offer(currNode.left);
}
if (currNode.right != null && !visited.contains(currNode.right)) {
q.offer(currNode.right);
}
TreeNode currParent = nodeParent.get(currNode);
if (currParent != null && !visited.contains(currParent)) {
q.offer(currParent);
}
}
return -1;
}

private void buildParentMap(Map<TreeNode, TreeNode> nodeParent, TreeNode node, TreeNode parent, int k) {
if (node == null) {
return;
}
nodeParent.put(node, parent);
if (node.val == k) {
startNode = node;
}
buildParentMap(nodeParent, node.left, node, k);
buildParentMap(nodeParent, node.right, node, k);
}
}

先DFS把parent都记录好, 然后再从k处BFS即可.

时间复杂度: O(n)
空间复杂度: O(n) 用了map存了每一个node的parent, 以及递归需要用栈.